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(F)=2F^2-2F+6
We move all terms to the left:
(F)-(2F^2-2F+6)=0
We get rid of parentheses
-2F^2+F+2F-6=0
We add all the numbers together, and all the variables
-2F^2+3F-6=0
a = -2; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·(-2)·(-6)
Δ = -39
Delta is less than zero, so there is no solution for the equation
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